Dist. fr A-C to B = 8 + 9 = 8.5 = (A to B)
+ (C to B)
2
2
Dist. fr A-C to D = 12 + 11 = 11.5 = (A to D)
+ (C to D)
2 2
First node
unites A & C with branch lengths of 7/2 = 3.5
Second
node unites the A-C clade with B with branch length
of 8.5/2 = 4.25
Third node
unites A-C-B with D with branch length of 12.33/2 = 6.17
Internode distances can be calculated by
subtraction
Node 1 to Node 2 = (Node 2 to
B) - ("Height" of Node 1)
= 4.25 - 3.5 = 0.75
"Height" of Node 1
can be taken from EITHER branch length 1-A or 1-C because
branch lengths from any node to tip are equal by
definition
Node 2 to Node 3 = (Node 2 to
D) - ("Height of Node 2)
= 6.17
- 4.25 = 1.91667