UPMGA Tree
—
D
11
—
 
 
C
14
9
—
B
12
7
8
—
A
D
C
B
A
OTU
—
D
14
—
B
11.5
8.5
—
A-C
D
B
A-C
OTU
Dist. fr A-C to B = 8 + 9 = 8.5 = (A to B) + (C to B)
                                  2                              2
Dist. fr A-C to D = 12 + 11 = 11.5 = (A to D) + (C to D)
                                    2                                 2
Dist. fr A-C-B to D = 12 + 14 + 11 = 12.33333
                                           3
=  (A to D) + (B to D) + (C to D)
                          3
First node unites A & C with branch lengths of 7/2 = 3.5
Second node unites the A-C clade with B with branch length of 8.5/2 = 4.25
Third node unites A-C-B with D with branch length of 12.33/2 = 6.17
Internode distances can be calculated by subtraction
Node 1 to Node 2 = (Node 2 to B) - ("Height" of Node 1)
        = 4.25 - 3.5 = 0.75
"Height" of Node 1 can be taken from EITHER branch length 1-A or 1-C because branch lengths from any node to tip are equal by definition
Node 2 to Node 3 = (Node 2 to D) - ("Height of Node 2)
        = 6.17 - 4.25 =  1.91667
UPGMAfig2
2
3
UPGMAfig
http://www.dina.dk/~sestoft/bsa/Match7Applet.html
4
5
1
29